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Merge pull request #1257 from github/rasmuswl/fix-ubuntu22.04-venv-creation
python-setup: Fix venv creation in Ubuntu 22.04
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@@ -5,6 +5,7 @@ import os
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import subprocess
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from tempfile import mkdtemp
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from typing import Optional
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import shutil
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import extractor_version
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@@ -167,6 +168,19 @@ def install_packages(codeql_base_dir) -> Optional[str]:
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# get_extractor_version returns the Python version the extractor thinks this repo is using
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version = extractor_version.get_extractor_version(codeql_base_dir, quiet=False)
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sys.stdout.flush()
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sys.stderr.flush()
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if version == 2 and not sys.platform.startswith('win32'):
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# On Ubuntu 22.04 'python2' is not available by default. We want to give a slightly better
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# error message than a traceback + `No such file or directory: 'python2'`
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if shutil.which("python2") is None:
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sys.exit(
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"Python package installation failed: we detected this code as Python 2, but the 'python2' executable was not available. "
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"To enable automatic package installation, please install 'python2' before the 'github/codeql-action/init' step, "
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"for example by running 'sudo apt install python2' (Ubuntu 22.04). "
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"If your code is not Python 2, but actually Python 3, please file a bug report at https://github.com/github/codeql-action/issues/new"
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)
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if os.path.exists('requirements.txt'):
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print('Found requirements.txt, will install packages with pip', flush=True)
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